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10x^2+40x-210=0
a = 10; b = 40; c = -210;
Δ = b2-4ac
Δ = 402-4·10·(-210)
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{10000}=100$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-100}{2*10}=\frac{-140}{20} =-7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+100}{2*10}=\frac{60}{20} =3 $
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